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Year 11 / Mathematical Methods / Term 1 / Weeks 01 02 / Teacher

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Public teacher-targeted worked key and next movesYear 11 Methods · T1 W1–2 · Teacher · Key And Next

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Teacher copy · prompts and answer keys

Teacher copy: This page may include teaching prompts or answer keys. Answer keys in this public library can be viewed by anyone. Give learners a clean prompt, use checks as formative evidence, and change a case locally when prior access matters.

This key is reachable by anyone with the pack URL. The two checks are fresh relative to practice, not secure examinations. Collect first responses before displaying a model. Accept equivalent exact forms only when the expression is genuinely equal; approximate values require ≈. Spoken and tactile routes still need captured exact notation and justification.

Card answers and teaching checks

Card Worked result and important reason
A sqrt(9)=3, sqrt(16)=4; sqrt(10) is irrational and is a surd because 10 is not a perfect square. 3<sqrt(10)<4. sqrt(10)≈3.162, never exact equality to rounded 3.16.
B 72=36×2, so sqrt(72)=6sqrt(2), and (6sqrt(2))²=36×2=72. Since 64<72<81, 8<sqrt(72)<9. Square-root splitting does not apply to a sum.
C sqrt(50)=5sqrt(2), sqrt(98)=7sqrt(2); second longer by 2sqrt(2) units.
D sqrt(12)=2sqrt(3) and sqrt(27)=3sqrt(3), giving 5sqrt(3) cm, about 8.66 cm. sqrt(39) lies between 6 and 7, so it cannot be the sum. sqrt(12)+sqrt(8)=2sqrt(3)+2sqrt(2) cannot combine further as like surds.
E sqrt(32)-sqrt(8)=4sqrt(2)-2sqrt(2)=2sqrt(2) cm. sqrt(8)+sqrt(18)=2sqrt(2)+3sqrt(2)=5sqrt(2) cm.
F sqrt(6)sqrt(15)=sqrt(90)=3sqrt(10) cm², approximately 9.49 cm². (2sqrt(3))(3sqrt(6))=6sqrt(18)=18sqrt(2).
G 7/sqrt(5)×sqrt(5)/sqrt(5)=7sqrt(5)/5; top and bottom are multiplied by the same nonzero factor, so value is unchanged. 4/sqrt(2)=4sqrt(2)/2=2sqrt(2).
H sqrt(18)=3sqrt(2), sqrt(8)=2sqrt(2), so the fraction is 5sqrt(2)/sqrt(2)=5. Alternatively sqrt(18)/sqrt(2)+sqrt(8)/sqrt(2)=sqrt(9)+sqrt(4)=3+2=5. The invalid draft replaces a sum of roots by the root of a sum. sqrt(26)/sqrt(2)=sqrt(13)≈3.61, not 5.
I Table for x=0,1,2,3,4 gives y=5,2,1,2,5. Turning point (2,1), axis x=2, y-intercept (0,5), no real x-intercepts because (x-2)²+1≥1.
J Zeros x=-1,3; axis x=1; turning point (1,-4) from (2)(-2)=-4; y-intercept (0,-3); opens up because x² coefficient is +1; y<0 for -1<x<3.

Check A · Day 5

243=81×3 gives sqrt(243)=9sqrt(3) cm. 48=16×3 gives sqrt(48)=4sqrt(3) cm. Difference is 5sqrt(3) cm, approximately 8.7 cm to one decimal (5×1.73205…≈8.66025). The draft's sqrt(195) is approximately 14.0 cm; it is not 5sqrt(3). More fundamentally, sqrt(a)-sqrt(b) cannot be turned into sqrt(a-b) for these nonnegative a,b. A valid exact comparison squares positive values: (5sqrt(3))²=75, while (sqrt(195))²=195.

Respond: if factor extraction fails, supply a square-number list and ask for 81×3 and 16×3. If terms are combined as sqrt(195), ask the learner to square both proposed positive values. If the calculation is correct but = is used for 8.7, practise exact versus approximate notation. If secure, use a fresh invented unlike-radical pair and ask why it cannot combine.

Check B · Day 10

For y=-(x-2)(x-8), zeros are (2,0) and (8,0). The axis is their midpoint x=5. At x=5, y=-[(3)(-3)]=9, so the turning point is (5,9). At x=0, y=-[(-2)(-8)]=-16, so y-intercept (0,-16). The negative x² coefficient makes the parabola open downward. Between the zeros, e.g. x=5, the product (x-2)(x-8) is negative, so its negative is positive; the graph is above the x-axis for 2<x<8 and equals zero at the endpoints. 5/sqrt(11)×sqrt(11)/sqrt(11)=5sqrt(11)/11; sqrt(11) is nonzero, so the multiplier is 1.

Respond: if the midpoint 5 is reported as the turning height, substitute x=5 to obtain 9. If the sign interval is reversed, test x=5 and x=0. If a learner rationalises only the numerator, compare approximate values of old and new forms. If secure, test a new factor-form curve with unequal roots and a non-unit coefficient. The check samples only a small part of the quadratic-function sub-topic.

Optional swaps · worked results

Day Swap 1 Swap 2
1 sqrt(25)=5; sqrt(7) surd and 2<sqrt(7)<3 sqrt(49)=7; sqrt(15) surd and 3<sqrt(15)<4
2 sqrt(108)=sqrt(36×3)=6sqrt(3); square gives 108 sqrt(200)=sqrt(100×2)=10sqrt(2); square gives 200
3 sqrt(18)=3sqrt(2), sqrt(72)=6sqrt(2); difference 3sqrt(2) cm sqrt(27)=3sqrt(3), sqrt(75)=5sqrt(3); difference 2sqrt(3) cm
4 sqrt(20)+sqrt(45)=2sqrt(5)+3sqrt(5)=5sqrt(5) cm sqrt(28)+sqrt(63)=2sqrt(7)+3sqrt(7)=5sqrt(7) units
5 sqrt(75)-sqrt(27)=5sqrt(3)-3sqrt(3)=2sqrt(3) cm, positive sqrt(125)-sqrt(20)=5sqrt(5)-2sqrt(5)=3sqrt(5) cm
6 sqrt(8)sqrt(18)=sqrt(144)=12 cm² (3sqrt(2))(2sqrt(10))=6sqrt(20)=12sqrt(5)
7 5/sqrt(3)=5sqrt(3)/3 6/sqrt(7)=6sqrt(7)/7, both ≈2.2678
8 (sqrt(50)+sqrt(8))/sqrt(2)=(5sqrt(2)+2sqrt(2))/sqrt(2)=7 (sqrt(75)-sqrt(12))/sqrt(3)=(5sqrt(3)-2sqrt(3))/sqrt(3)=3
9 (−1,2), x=−1, (0,3), no real zeros since y≥2 (1,3), x=1, (0,5), no real zeros since y≥3; x=0 and x=2 both yield y=5
10 Zeros 2,6; axis x=4; vertex (4,−4); y-intercept (0,12), opens up Zeros −2,4; axis x=1; vertex (1,9); y-intercept (0,8), opens down; at x=1 y=9>0

Scope: these key values support feedback on initial surd skills and first quadratic features. They do not cover quadratic formula, completing the square, discriminant, full curve sketching or modelling. School assessment design remains with the school.