0–3 puzzle: Show 18.0 and 27.0 without the device note; ask what the displayed decimal alone proves. 3–7 source: Reveal the stipulated ±0.1 °C uncertainty per reading and no calibration evidence. 7–12 teach: On temperature-record, subtract 27.0−18.0=9.0 °C; add stated absolute bounds conservatively to ±0.2 °C for this difference. Percentage uncertainty 0.2/9.0×100≈2.2%. Distinguish resolution/display, uncertainty and accuracy. 12–20 route: A/B/C shows the bounded result and edits the note. 20–23 audit: Ask whether repeated identical readings would prove no bias (no). 23–25 exit: Report ΔT=(9.0±0.2) °C, approximately 2.2% uncertainty, and one calibration unknown.
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Day 7 · A digit is not an accuracy certificateYear 11 Physics · T1 W1–2 · Day 7 lesson
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Year 11 / Physics / Term 1 / Weeks 01 02
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