0–3 puzzle: Compare the fictional tile labels before revealing c; ask if equal input alone fixes ΔT. 3–7 source: Reveal same 0.50 kg, 3,000 J input and different stipulated c values. 7–12 teach: Rearrange ΔT=Q/(mc) on heat-budget. Aster: 3,000/(0.50×1,000)=6 K; Beryl: 3,000/(0.50×2,000)=3 K. These constants are invented, with no phase change or loss. 12–20 route: Learners compare the result and edit “whatever they are made of”. 20–23 audit: Have a partner name the fixed variables and the one changed variable. 23–25 exit: Which model c leads to a smaller temperature rise, and why?
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Day 9 · Specific heat capacity changes the answerYear 11 Physics · T1 W1–2 · Day 9 lesson
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Year 11 / Physics / Term 1 / Weeks 01 02
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