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Enough for complete sections?Year 8 Maths · T1 W5–6 · H08

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A diagram has 2 m of usable stock. Each complete section needs 3/10 m. Find how many complete sections fit and what length remains. Explain why a calculator quotient alone does not answer the complete-section question.

A way to check: 2 ÷ (3/10) = 20/3 = 6⅔ section-lengths. Six full sections use 9/5 m; 1/5 m remains. Seven would need 21/10 m, more than the stock.