Code: AC9M3N03 (partial). Goal: solve a three-digit subtraction with transparent exchanges and verify by addition. Prepare: H/T/O cards, open number line.
- Invite · 2. Show
705 − 368; ask whether an answer over 705 could be sensible, and why the empty tens place matters. - Model · 5. Start
7H 0T 5O. Exchange one H for ten T, then one of those T for ten O:6H 9T 15O. Remove3H 6T 8O→3H 3T 7O = 337. Check337 + 368 = 705. - Guided · 6. Work
602 − 157together. Exchange to5H 9T 12O; subtract →4H 4T 5O = 445. Draw the exchange arrows rather than saying “borrow”. - Choice · 6. Choose one D19 card. Learner may use exchange cards or count up from the smaller quantity. Check by addition and name the unit.
- Exit · 4. Solve
503 − 268; expected 235. If a learner says 345, rebuild the hundred-to-ten and ten-to-one exchanges one at a time. - Note · 2. Record whether the child conserved the total during exchanges and checked independently.
Access/home/extension: Use labelled, touchable groups; a scribe may move pieces only as directed. At home, use invented quantities of blank cards. Extension: count up 368→400 (+32)→700 (+300)→705 (+5), total 337, and compare with regrouping.