Codes: AC9M8A02. Goal: solve a two-step linear equation, including a rational solution in practice, and verify by substitution. Prepare: balance/rearrange mat.
- Launch · 2 min. Ask what equality means in
3x+7=25: both sides hold the same value. - Model · 5 min. Subtract 7 on both sides, divide both sides by 3:
x=6. Substitute:3×6+7=25. The balance picture helps explain inverse operations. - Guided · 6 min. Solve
2y+5=12:2y=7,y=7/2=3.5; substitute2×3.5+5=12. A rational answer is legitimate when the variable has no whole-number domain restriction. - Practice · 6 min. D16-A/B/C solve distinct rational-result equations, with tiles, spoken balancing or error critique. Require exact fraction/decimal and substitution.
- Exit · 4 min. In
4z−3=9,z=3; check4×3−3=9. Ask why adding 3 happens before dividing 4. - Note · 2 min. If a learner alters one side only, use the balance mat; if arithmetic slips, preserve algebra evidence and check with calculator after setup.
Later: Day16 extra uses a negative starting constant.