Success: critique a convenience sample without calling its arithmetic wrong. (AC9M8ST01, AC9M8ST02, AC9M8ST04)
- See · 2 min. Display rack C: 16 bicycles out of 20; ask for its sample percentage.
- Model · 4 min.
16/20=80%, which is correct for C. Because selection was beside racks, it may overrepresent cyclists; it cannot estimate all students well. - Guided compare · 5 min. Contrast C's 80%, random model A's 15%, B's 20% and known fictional population's 20%. Ask which source answers each narrower question.
- Independent critique · 7 min. Learners write a two-line correction to “80% of all students cycle”: valid sample result plus uncertainty about population.
- Fairness talk · 4 min. Ask why a shelter decision based on the rack sample could overlook bus users. Do not ask anyone to disclose their own travel.
- Exit · 3 min. “What is wrong:
16/20=80%or calling that 80% of all students?” Key: the population inference.