Success: choose a benchmark for a larger-number product, calculate and explain why the exact result is plausible. Prepare: first model in MATERIALS, blank estimate mat. Codes: AC9M5N06, AC9M5N08.
- Recall · 2 min. Ask if
50×20is a useful scale for48×19. Key: yes, about 1,000; it is not the exact seat count. - Model · 5 min. On the invented 48-by-19 stand, show
48×(20−1)=960−48=912. Both factors were rounded up for 1,000, so an answer above 1,000 would deserve a recheck. Say the original unit is drawn seats, not attendance. - Guide · 6 min. Compare
246×4with250×4=1,000. Partition246×4=(200+40+6)×4=800+160+24=984. Ask which estimate is intentionally a little high and why. - Choose · 7 min. Offer one Day 11 A/B/C card. Ask for an estimate before exact multiplication, a visible method and one sentence comparing them.
- Exit · 3 min. “Would 9,120 be reasonable for 48×19?” Key: no, about ten times a useful benchmark. Repair a misplaced zero with the bound.
- Record · 2 min. Note estimate, exact value and explanation separately. A child's reasonable estimate can be sound even if their exact arithmetic needs reteaching.