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Day 14 · Choose a strategy that helpsYear 5 Maths · T1 W3–4 · Day 14 lesson

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Year 5 / Mathematics / Term 1 / Weeks 03 04

Part of the full two-week lesson sequence. Check the pack guide and taught point before teaching.

Open for this lesson: Pack guide · Sources and materials · Worked swaps · Aids and text routes.

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Success: use compensation, partitioning or a standard algorithm deliberately and explain a bound. Prepare: 247×18 model. Codes: AC9M5N06, AC9M5N08.

  1. Recall · 2 min. Ask why 18 might be rewritten as 20−2. Key: 20 is easy to multiply by; subtract two extra groups.
  2. Model · 5 min. Show 247×18=247×20−247×2=4,940−494=4,446. Check against 250×18=4,500; exact is 54 below because each of 18 groups has 3 fewer.
  3. Guide · 6 min. Compare 125×32=(125×(4×8)) with 125×(30+2)=3,750+250=4,000. A learner may use 125×8=1,000 then ×4=4,000. Ask why either route is efficient here, and why 125×30 is 3,750 rather than 375.
  4. Choose · 7 min. Day 14 A/B/C route with two possible strategies; child selects and defends one. Correct alternatives count if exact and inspectable.
  5. Exit · 3 min. “Is 44,460 a reasonable result for 247×18?” Key: no; scale near 4,500, about ten times smaller. Revisit place alignment if needed.
  6. Record · 2 min. Note choice, correctness and reasonableness separately; do not insist on one prescribed algorithm.

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