Codes: AC9M10A02, AC9M10A04. Goal: solve a pair of linear equations and interpret the graphical intersection. Prepare: cost models and axes 0–12 months, $0–$1,300.
- Predict · 2 min. “Plan A starts cheaper but rises faster. Could the totals meet?” Ask for a reasoned guess.
- Model algebra · 5 min. Set
240+80m=480+50m. Subtract50mand $240:30m=240, so m=8. Substitute: both $880. - Graph check · 6 min. Plot each plan at m=0 and m=8; straight lines meet at
(8 months, $880). Discuss that the intersection means equal modelled cost, not equal service quality. - Independent comparison · 7 min. Compare m=6: A $720, B $780, so A cheaper by $60. Compare m=10: A $1,040, B $980, so B cheaper by $60. Ask why ordering reverses.
- Error check · 3 min. Show
30m=240 → m=30/240. Repair the inverse operation and substitute to test 8. - Exit · 2 min. Everyone states the crossing coordinate with both units and one model limit.
Access: tactile crossing lines or paired value table; demonstrate equality by substitution without demanding visual graph reading.